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प्रश्न
If sin (θ + 36°) = cos θ, where (θ + 36°) is acute, find θ.
बेरीज
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उत्तर
Given: sin(θ + 36°) = cos θ, where (θ + 36°) is acute.
Step-wise calculation:
1. cos θ = sin(90° – θ), so sin(θ + 36°) = sin(90° – θ).
2. Since θ + 36° is acute and 90° – θ is acute, equate the angles:
θ + 36° = 90° – θ
3. Solve: 2θ = 54°
⇒ θ = 27°
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