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प्रश्न
If sin θ = 0.6, find sec θ + tan θ.
बेरीज
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उत्तर
Given:
sin θ = 0.6 = `3/5`
In a right triangle, if sin θ = `3/5` then:
Opposite side = 3θ
Hypotenuse = 5θ
adjacent side = `sqrt((5θ)^2 − (3θ)^2) = sqrt (25θ^2 − 9θ^2) = 4θ`
`cos θ = 4/5, sec θ = 5/4`
tan θ = `"opposite"/"adjacent" = 3/4`
sec θ + tan θ = `5/4 + 3/4 = 8/4`
sec θ + tan θ = 2
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