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प्रश्न
If sec θ + tan θ = m, then the value of sec4 θ – tan4 θ – 2 sec θ tan θ is ______.
रिकाम्या जागा भरा
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उत्तर
If sec θ + tan θ = m, then the value of sec4 θ – tan4 θ – 2 sec θ tan θ is `underlinebb(1/m^2)`.
Explanation:
sec4θ – tan4θ = (sec2θ – tan2θ)(sec2θ + tan2θ)
= 1·(sec2θ + tan2θ) ...(Since sec2θ – tan2θ = 1)
Using this, sec4θ – tan4θ – 2 secθ tanθ
= sec2θ + tan2θ – 2 secθ tanθ
= (secθ – tanθ)2
But (secθ + tanθ)(secθ – tanθ) = 1.
So `secθ - tanθ = 1/(secθ + tanθ) = 1/m`.
Therefore the expression equals `(1/m)^2 = 1/m^2`.
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