Question

If sec 2A = cosec (A – 42°) where 2A is an acute angle, find the value of A.

Answer 1

We know that (sec (90 – θ)) = cosec θ

sec 2A = sec (90 – (A – 42))

sec 2A = sec (90 – A + 42)

sec 2A = sec (132 – A)

Now equating both the angles we get

2A = 132 – A

`3A = 132/3`

A= 44