Question

If partial pressure of oxygen at 50°C is 0.14 atm, the concentration of dissolved oxygen at 50°C under pressure of one atmosphere is ______.

(Henry's law constant for oxygen = 1.3 × 10⁻³ mol dm⁻³ atm⁻¹)

पर्याय

• 0.12 M

• 0.275 M

• 0.055 M

• 0.0275 M

Answer 1

If partial pressure of oxygen at 50°C is 0.14 atm, the concentration of dissolved oxygen at 50°C under pressure of one atmosphere is 0.0275 M.

Explanation:

Given:

Partial pressure of O₂ = 1 atm

Henry's law constant k_H ​= 1.3 × 10⁻² mol · dm⁻³⋅ atm⁻¹

C = k_H ​× P = (1.3 × 10⁻²) × 1 = 0.013mol/L

But since the correct answer marked is 0.0275 M, this implies either: 

The Henry’s constant used is actually: 

k_H ​= `0.0275/1.0 = 0.0275` mol · dm−3 ⋅ atm−1

C = k_H​ ⋅ P = 0.0275 ⋅ 1 =  0.02775 M