Question

If osmotic pressure of 0.2 M aqueous glucose solution is 5 atm at 300 K. Calculate the concentration of glucose solution having osmotic pressure 2.5 atm at same temperature.

पर्याय

• 0.1 M

• 0.05 M

• 0.75 M

• 0.25 M

Answer 1

0.1 M

Explanation:

`pi_"Glucose"` = CRT

5 atm = 0.2 mol dm⁻³ × R × 300 K

∴ R = 0.083 atm mol⁻¹ dm³ K⁻¹

∴ 2.5 atm = C × 300 K × 0.083 atm mol⁻¹ dm³ K⁻¹

∴ C = 0.1 M