Advertisements
Advertisements
प्रश्न
If logα8 = γ, logβα = –1 and log1/4β = –1 then `(1/α + 1)^(log_sqrt(5)(β^2 + 4γ^2)` is equal to ______.
पर्याय
`sqrt(5)`
5
25
625
MCQ
रिकाम्या जागा भरा
Advertisements
उत्तर
If logα8 = γ, logβα = –1 and log1/4β = –1 then `(1/α + 1)^(log_sqrt(5)(β^2 + 4γ^2)` is equal to 625.
Explanation:
logα8 = γ, logβα = –1, log1/4β = –1
⇒ β = 4, α = `1/4`, γ = `-3/2`
⇒ `(1/α + 1)^(log_sqrt(5)(β^2 + 4γ^2)) = 5^(log_sqrt(5)(16 + 9)`
= `5^(log_(5 1/2) 5^2)`
= 54
= 625
shaalaa.com
Fundamental Integrals Involving Logarithms Functions
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
