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प्रश्न
If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times, the least, then the numbers are
पर्याय
5, 10, 15, 20
4, 101, 16, 22
3, 7, 11, 15
none of these
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उत्तर
Here, we are given that four numbers are in A.P., such that their sum is 50 and the greatest number is 4 times the smallest.
So, let us take the four terms as a - d , a , a + d , a + 2d.
Now, we are given that sum of these numbers is 50, so we get,
( a - d ) + (a) + ( a+ d ) + ( a + 2d) = 50
a - d + a + a + d + a + 2d = 50
4a + 2d = 50
2a + d = 25 ............(1)
Also, the greatest number is 4 times the smallest, so we get,
a +2d = 4 ( a - d)
a + 2d = 4a - 4d
4d + 2d = 4a - a
6 d = 3a
`d = 3/6 a ` ....................(2)
Now, using (2) in (1), we get,
`2a + 3/6 a = 25`
`(12a + 3a)/6 = 25 `
15a = 150
` a = 150/15`
a = 10
Now, using the value of a in (2), we get,
`d = 3/6 (10)`
` d = 10/2`
d = 5
So, first term is given by,
a - d = 10 - 5
= 5
Second term is given by,
a = 10
Third term is given by,
a + d = 10 + 5
= 15
Fourth term is given by,
a + 2d = 10 + (2) (5)
= 10 + 10
= 20
Therefore, the four terms are 5, 10 , 15, 20.
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