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प्रश्न
If `cos θ = 4/5` then tan θ = ?
पर्याय
`3/4`
`4/3`
`3/5`
`5/3`
MCQ
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उत्तर
`bb(3/4)`
Explanation:

`cos θ = 4/5`
⇒ `(AB)/(AC) = 4/5`
Let AB = 4k and AC = 5k. Then,
BC2 = (AC2 – AB2)
= (25k2 – 16k2)
= 9k2
⇒ `BC = sqrt(9k^2)`
⇒ BC = 3k.
∴ `tan θ = (BC)/(AB)`
= `(3k)/(4k)`
= `3/4`
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