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प्रश्न
If cos θ = `11/61`, find tan θ.
बेरीज
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उत्तर
Base (adjacent side) = 11
Hypotenuse = 61
Use Pythagoras Theorem to find Perpendicular
Perpendicular2 = Hypotenuse2 − Base2
Perpendicular2 = 612 − 112 = 3721
Perpendicular2 = 3721 − 121 = 3600
Perpendicular = `sqrt3600`
Perpendicular = 60
tan θ = `"Perpendicular"/"Base"` ...(formula for tangent)
tan θ = `60/11`
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