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प्रश्न
If α = `cos^-1(3/5)`, β = `tan^-1(1/3)`, where 0 < α, β < `π/2`, then α – β is equal to ______.
पर्याय
`sin^-1(9/(5sqrt(10)))`
`cos^-1(9/(5sqrt(10)))`
`tan^-1(9/(5sqrt(10)))`
`tan^-1(9/14)`
MCQ
रिकाम्या जागा भरा
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उत्तर
If α = `cos^-1(3/5)`, β = `tan^-1(1/3)`, where 0 < α, β < `π/2`, then α – β is equal to `underlinebb(sin^-1(9/(5sqrt(10))))`.
Explanation:
| cosα = `3/5` tanβ = `1/3` | |
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sin(α – β) = sinαcosβ – cosαsinβ
= `4/5 xx 3/sqrt(10) - 3/5 xx 1/sqrt(10)`
sin(α – β) = `9/(5sqrt(10))`
⇒ α – β = `sin^-1(9/(5sqrt(10)))`
shaalaa.com
Trigonometric Equations
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