Advertisements
Advertisements
प्रश्न
If a : b : : c : d, then prove that
2a+7b : 2a-7b = 2c+7d : 2c-7d
Advertisements
उत्तर
2a+7b : 2a-7b = 2c+7d : 2c -7d
`"a"/"b" = "c"/"d"`
Multiplying both sides by `2/7`
`=> "a"/"b" xx 2/7 = "c"/"d" xx 2/7`
`=> (2"a")/(7"b") = (2"c")/(7"d")`
Applying componendo and dividendo,
`(2"a" + 7"b")/(2"a" - 7"b") = (2"c" + 7"d")/(2"c" - 7"d")`
Hence, 2a+7b : 2a-7b = 2c+7d : 2c-7d
APPEARS IN
संबंधित प्रश्न
Find the third proportional to `2 2/3` and 4
Check whether the following numbers are in continued proportion.
9, 12, 16
Find the value of the unknown in the following proportion :
`1/2 : "m" :: 14/9 : 4/3`
If a : b = c : d; then show that (ax+ by) : b = (cx+ dy) : d
If u, v, w, and x are in continued proportion, then prove that (2u+3x) : (3u+4x) : : (2u3+3v3) : (3u3+4v3)
`("pqr")^2 (1/"p"^4 + 1/"q"^4 + 1/"r"^4) = ("p"^4 + "q"^4 + "r"^4)/"q"^2`
Show that the following numbers are in continued proportion:
48, 60, 75
Find the value of x if 5 : 3 : : x : 6.
If Rs 760 is divided between A and B in the ratio 8 : 11, then B's share is
If a, b, c, d are in continued proportion, prove that: `(a^3 + b^3 + c^3)/(b^3 + c^3 + d^3) = a/d`
Fill the boxes using any set of suitable numbers 6 : `square` : : `square` : 15
