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प्रश्न
If α and β are zeroes of a quadratic polynomial px2 + qx + 1. Form a quadratic polynomial whose zeroes are `2/α` and `2/β`.
बेरीज
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उत्तर
Given: Let α and β be the zeros of px2 + qx + 1. Then `α + β = -q/p` and `αβ = 1/p`.
Step-wise calculation:
1. Sum of the new zeros:
`2/α + 2/β = (2(α + β))/(αβ)`
= `(2(-q/p))/(1/p)`
= –2q
2. Product of the new zeros:
`(2/α)(2/β) = 4/(αβ)`
= `4/(1/p)`
= 4p
3. Form the monic quadratic x2 – (sum)x + (product):
x2 – (–2q)x + 4p
= x2 + 2qx + 4p
A quadratic polynomial whose zeros are `2/α` and `2/β` is x2 + 2qx + 4p more generally k(x2 + 2qx + 4p) for any nonzero constant k.
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