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प्रश्न
If α and β are the zeros of the quadratic polynomial f(x) = x2 – 5x + 4, find the value of `1/α + 1/β - 2αβ`.
बेरीज
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उत्तर
Given: If α and β are the zeros of f(x) = x2 – 5x + 4, find `1/α + 1/β - 2αβ`.
Step-wise calculation:
1. For f(x) = x2 – 5x + 4.
Compare with ax2 + bx + c:
a = 1, b = –5, c = 4
Hence `α + β = -b/a = 5` and `αβ = c/a = 4`.
2. `1/α + 1/β = (α + β)/(αβ)`
= `5/4`
3. 2αβ = 2 × 4
= 8
4. Therefore `1/α + 1/β - 2αβ = 5/4 - 8`
= `5/4 - 32/4`
= `−27/4`
The value is `-27/4` (which is –6.75).
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