मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

If α and β are the roots of the equation is 3x2 + x – 10 = 0, then the value of αβ1α+1β is ______. - Algebra

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प्रश्न

If α and β are the roots of the equation is 3x2 + x – 10 = 0, then the value of `1/α + 1/β` is ______.

पर्याय

  • 10

  • `- 1/10`

  • `1/10`

  • `1/3`

MCQ
रिकाम्या जागा भरा
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उत्तर

If α and β are the roots of the equation is 3x2 + x – 10 = 0, then the value of `1/α + 1/β` is `underline(1/10)`.

Explanation:

Given equation is, 3x2 + x – 10 = 0

Since α and β are the roots of given equation

∴ Sum of roots (α + β) = `(-b)/a = (-1)/3`

Product of roots (αβ) = `c/a = (-10)/3`

Now, `1/α + 1/β = (β + α)/(αβ)`Quadratic Equations

= `((-1)/3)/((-10)/3)`

= `(-1)/3 xx 3/(-10)`

= `1/10`

Thus, the value of `1/α + 1/β` is `1/10`.

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