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प्रश्न
If ΔABC ~ ΔDEF, AB = 4 cm, DE = 6 cm, EF = 9 cm and FD = 12 cm, then the perimeter of ΔABC is ______.
रिकाम्या जागा भरा
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उत्तर
If ΔABC ~ ΔDEF, AB = 4 cm, DE = 6 cm, EF = 9 cm and FD = 12 cm, then the perimeter of ΔABC is 18 cm.
Explanation:
Since ΔABC ~ ΔDEF, corresponding sides are proportional `((AB)/(DE) = (BC)/(EF) = (CA)/(FD))`.
`(AB)/(DE) = 4/6 = 2/3`
So `BC = 2/3 xx 9 = 6` cm and `CA = 2/3 xx 12 = 8` cm.
Perimeter = 4 + 6 + 8
= 18 cm
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