Question

If AB is a chord of length \[5\sqrt{3}\] cm of a circle with centre O and radius 5 cm, then area of sector OAB is 

पर्याय

• \[\frac{3\pi}{8}c m^2 \] 

• \[\frac{8\pi}{3}c m^2\]

• \[25 \pi cm^2\]

• \[\frac{25\pi}{3}c m^2\]

Answer 1

We have to find the area of the sector OAB. 

We have, 

`AM=(5sqrt3)/2`

So, 

sin` ∠ AOM=(5sqrt3)/(2(5))`

Hence, 

`∠ AOM=60°`

Therefore area of the sector, 

`=1/2r^2θ`

`=1/2 (25)(2pi/3)`

`=(25pi)/3 cm^2`