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प्रश्न
If A is an event of a random experiment such that `"P"("A"):"P"(bar"A")` = 17 : 15 and n(S) = 640 then find `"P"(bar"A")`
बेरीज
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उत्तर
`"P"("A"):"P"(bar"A")` = 17 : 15
`("P"("A"))/("P"(bar"A")) = 17/15`
⇒ `(1 - "P"(bar"A"))/("P"(bar"A")) = 17/15`
`17 "P"(bar"A") = 15 [1 - "P"(bar"A")]`
= `15 - 15 "P"(bar"A")`
`17 "P"(bar"A") + 15 "P"(bar"A")` = 15
⇒ `32 "P"(bar"A")` = 15
`"P"(bar"A") = 15/32`
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