Advertisements
Advertisements
प्रश्न
If `3x - (1)/(3x) = 9`; find the value of `27x^3 - (1)/(27x^3)`.
Advertisements
उत्तर
`3x - (1)/(3x) = 9`
Using `("a" - (1)/"a")^3`
= `"a"^3 - (1)/"a"^3 - 3("a" - 1/"a")`, we get :
`(3x - 1/(3x))^3`
= `(3x)^3 - (1/(3x))^3 -3(3x - 1/(3x))`
⇒ 729 = `27x^3 - (1)/(27x^3) - 3(9)`
⇒ `27x^3 - (1)/(27x^3)`
= 729 + 27
= 756.
APPEARS IN
संबंधित प्रश्न
Expand.
(k + 4)3
Simplify.
(3r − 2k)3 + (3r + 2k)3
If a + 2b + c = 0; then show that: a3 + 8b3 + c3 = 6abc.
Use property to evaluate : 73 + 33 + (-10)3
Use property to evaluate : 93 - 53 - 43
If a ≠ 0 and `a - 1/a` = 4; find: `(a^2 + 1/a^2)`
If a ≠ 0 and `a - 1/a` = 4 ; find : `( a^3 - 1/a^3 )`
If `x + (1)/x = 5`, find the value of `x^2 + (1)/x^2, x^3 + (1)/x^3` and `x^4 + (1)/x^4`.
If `"a" + (1)/"a" = "p"`; then show that `"a"^3 + (1)/"a"^3 = "p"("p"^2 - 3)`
Expand (2a + 5)3
