मराठी

If 3 F ( X ) + 5 F ( 1 X ) = 1 X − 3 for All Non-zero X, Then F(X) =(A)1 14 ( 3 X + 5 X − 6 )(B) 1 14 ( − 3 X + 5 X − 6 )(C) 1 14 ( − 3 X + 5 X + 6 )(D) None of These - Mathematics

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प्रश्न

If \[3f\left( x \right) + 5f\left( \frac{1}{x} \right) = \frac{1}{x} - 3\]  for all non-zero x, then f(x) =

पर्याय

  • (a)  \[\frac{1}{14}\left( \frac{3}{x} + 5x - 6 \right)\]

  • (b)  \[\frac{1}{14}\left( - \frac{3}{x} + 5x - 6 \right)\]

  • (c) \[\frac{1}{14}\left( - \frac{3}{x} + 5x + 6 \right)\]

  • (d) None of these

     
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उत्तर

(d) None of these

\[3f\left( x \right) + 5f\left( \frac{1}{x} \right) = \frac{1}{x} - 3\]

\[\text{ Multiplying (1) by } 3: \]

\[15 f\left( \frac{1}{x} \right) + 9 f(x) = \frac{3}{x} - 9 . . . . . (2)\]

\[\text{ Replacing x by}  \frac{1}{x}\text{ in } (1): \]

\[3 f\left( \frac{1}{x} \right) + 5 f(x) = x - 3 \]

\[\text{ Multiplying by } 5: \]

\[15 f\left( \frac{1}{x} \right) + 25 f(x) = 5x - 15 . . . . (3)\]

\[\text{ Solving (2) and (3) } : \]

\[ - 16 f(x) = \frac{3}{x} - 5x + 6\]

\[ \Rightarrow f(x) = \frac{1}{16}\left( - \frac{3}{x} + 5x - 6 \right)\]

 

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Notes

Disclaimer: The question in the book has some error, so, none of the options are matching with the solution. The solution is created according to the question given in the book.

 
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Functions - Exercise 3.6 [पृष्ठ ४४]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 3 Functions
Exercise 3.6 | Q 28 | पृष्ठ ४४
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