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प्रश्न
If `2 sin 2θ = sqrt(3)` and 0° < 2θ < 90°, then θ is equal to ______.
पर्याय
20°
30°
15°
60°
MCQ
रिकाम्या जागा भरा
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उत्तर
If `2 sin 2θ = sqrt(3)` and 0° < 2θ < 90°, then θ is equal to 30°.
Explanation:
`2 sin 2θ = sqrt(3)`
⇒ `sin 2θ = sqrt(3)/2`.
With 0° < 2θ < 90°.
The principal solution is 2θ = 60°.
So, θ = 30°.
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पाठ 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18D [पृष्ठ ३८१]
