Advertisements
Advertisements
प्रश्न
If 1020 oxygen molecules per second strike 4 cm2 of wall at an angle of 30° with the normal when moving at a speed of 2 × 103 ms−1, find the pressure exerted on the wall. (mass of one oxygen atom = 2.67 × 10−26 kg)
Advertisements
उत्तर
Mass of O2 atom = 16 × mass of 1 atom
= 16 × 1020 × 2.67 × 10−26
m = 42.72 × 10−6 kg
Momentum of the O2 molecule (P) = mv = 42.72 × 10−6 × 2 × 103
P = 85.44 × 10−3 kg ms−1
Momentum normal to the wall at angle 30°
= 85.44 × 10−3 × cos 30°
= 73.99104 × 10−3 kg ms−1
Pressure = `"F"/"A" = "Change in momentum"/"Area"`
= `(73.99104 xx 10^-3)/((4 xx 10^-2)^2)`
= `(73.99104 xx 10^-3 xx 10^4)/16`
= 4.62444 × 10
P = 46.2 Nm−2
APPEARS IN
संबंधित प्रश्न
Find the kinetic energy of 3 litre of gas at S.T.P given standard pressure is 1.013 × 105 N/m2.
Determine the pressure of nitrogen at 0°C if the density of nitrogen at N.T.P. is 1.25 kg/m3 and R.M.S. speed of the molecules at N.T.P. is 489 m/s.
The ratio γ = `"C"_"p"/"C"_"v"` for a gas mixture consisting of 8 g of helium and 16 g of oxygen is ____________.
The following graph represents the pressure versus number density for an ideal gas at two different temperatures T1 and T2. The graph implies
What is the microscopic origin of pressure?
A gas is at temperature 80°C and pressure 5 × 10−10 Nm−2. What is the number of molecules per m3 if Boltzmann’s constant is 1.38 × 10−23 J K−1
Estimate the total number of air molecules in a room of a capacity of 25 m3 at a temperature of 27°C.
Derive an expression for the pressure exerted by a gas on the basis of the kinetic theory of gases.
Temperature remaining constant, if you double the number of molecules in a box, the pressure will ______.
The velocities of five molecules are 2 m/s, 3 m/s, 4 m/s, 5 m/s and 6 m/s. Find the root mean square velocity of molecules.
