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प्रश्न
If `1/x + 2/y = 4` and `3/y - 1/x = 11` then
पर्याय
x = 2, y = 3
x = –2, y = 3
`x = (-1)/2, y = 3`
`x = (-1)/2, y = 1/3`
MCQ
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उत्तर
`bb(x = (-1)/2, y = 1/3)`
Explanation:
Let `u = 1/x` and `v = 1/y`.
Then the system becomes
u + 2v = 4
–u + 3v = 11
Add the equations:
5v = 15
⇒ v = 3
Substitute into u + 2v = 4:
u + 6 = 4
⇒ u = –2
So, `1/x = -2 ⇒ x = (-1)/2` and `1/y = 3 ⇒ y = 1/3`.
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