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How would you account for the following? [Fe(CN)6]3− is weakly paramagnetic, while [Fe(CN)6]4− is diamagnetic. - Chemistry (Theory)

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प्रश्न

How would you account for the following?

[Fe(CN)6]3− is weakly paramagnetic, while [Fe(CN)6]4− is diamagnetic.

सविस्तर उत्तर
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उत्तर

The difference in magnetic behaviour between [Fe(CN)6]3− and [Fe(CN)6]4− is due to their differing oxidation states and resulting electron configurations. In [Fe(CN)6]3−, iron is in the +3 oxidation state (Fe3+), which has a 3d5 configuration. Although cyanide (CN) is a strong field ligand and tends to pair electrons, in the case of Fe3+, one unpaired electron still remains even after pairing. This results in the complex being weakly paramagnetic. In contrast, in [Fe(CN)6]4−, iron is in the +2 oxidation state (Fe2+) with a 3d6 configuration. Due to the strong field nature of CN, all six electrons pair up within the lower energy t₂g orbitals. As a result, there are no unpaired electrons in the complex, making [Fe(CN)6]4− diamagnetic. Therefore, the magnetic behaviour directly correlates with the quantity of unpaired electrons in the d-orbitals of the central metal ion.

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पाठ 9: Coordination Compounds - Review Exercises [पृष्ठ ५४१]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
पाठ 9 Coordination Compounds
Review Exercises | Q 9.59 (ii) | पृष्ठ ५४१
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