Question

How many terms are there in the series 4, 7, 10, 13, ........,148?

Answer 1

The given series is 4, 7, 10, 13, ........,148

7 – 4 = 3, 10 – 7 = 3, 13 – 10 = 3, etc.

Thus, the given series is an A.P. with first term a = 4 and common difference d = 3.

Last term = l = 148

4 + (n – 1)(3) = 148

`=>` (n – 1) × 3 = 144

`=>` n – 1 = 48

`=>` n = 49

Thus, there are 49 terms in the given series.