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प्रश्न
How many moles of calcium carbonate (CaCO3) are present in 10 g of the substance ? (Ca = 40 u ; C = 12 u ; O = 16 u)
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उत्तर
Mass of calcium carbonate = 10g
Molecular mass of calcium carbonate = (1 × 40) + (1 × 12) + (3 × 16) = 100g
Number of moles in 100g of calcium carbonate = 1 mole
Therefore, number of moles in 10g of calcium carbonate is 0.1.
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| Species Property | H2O | CO2 | Na atom | MgCl2 |
| No. of moles | 2 | - | - | 0.5 |
| No. of particles | - | 3.011×1023 | - | - |
| Mass | 36g | - | 115 g | - |
