Question

How many electrons are involved in the reaction, when 0.40 F of electricity is passed through an electrolytic solution?

पर्याय

• 6.642 × 10²⁵

• 1.505 × 10²⁴

• 6.022 × 10²³

• 2.4088 × 10²³

Answer 1

2.4088 × 10²³

Explanation:

Given,

Quantity of charge (Q) passed = 0.40 F

= 0.40 × 96500 C

= 38600 C

We know that, Q = ne⁻

where, n = number of electrons

e⁻ = charge on electron (1.6020 × 10⁻¹⁹ C)

∴ n = `"Q"/"e"^- = (38600  "C")/(1.6020 xx 10^-19  "C") = 2.4088 xx 10^23`