Question

How is angular speed related to frequency of rotation \[n\]?

पर्याय

• \[\omega=2\pi/n\]

• \[\omega=n/(2\pi)\]

• \[\omega=2\pi n\]

• \[\omega=nt\]

Answer 1

One revolution corresponds to an angle of \[2\pi\]. At a frequency of \[n\] revolutions per second, \[\omega=2\pi n\].