- To convert the NaCl structure into the CsCl structure, the size of the cations must be increased.
- In the NaCl structure, which is a face-centred cubic (FCC) lattice, the coordination number is 6 : 6, meaning each Na+ ion is surrounded by six Cl⁻ ions and vice versa.
- This structure is stable when the radius ratio `(r_+/r_-)` is approximately between 0.414 and 0.732.
- However, the CsCl structure has a body-centred cubic (BCC) arrangement with a coordination number of 8 : 8.
- For this structure to be stable, the radius ratio must be greater than 0.732. Therefore, by replacing Na+ ions with larger Cs+ ions, the radius ratio increases sufficiently to allow a transition from the NaCl (FCC) structure to the CsCl (BCC) structure.
- This substitution changes the ionic arrangement, enabling each ion to be surrounded by eight oppositely charged ions, thus forming the CsCl-type crystal lattice.
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प्रश्न
How can you convert NaCl structure into CsCl structure?
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उत्तर
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पाठ 1: Solid State - VERY SHORT ANSWER TYPE QUESTIONS [पृष्ठ ४२]
