Question

How are various lines of Lyman series formed? Explain on the basis of Bohr’s theory.

Answer 1

We know, 

`1/lambda = "R"_∞ [1/("n"_"f"^2 )- 1/"n"_"i"^2]`

If n_i = 2,3,4

n_f =1

For the member, n_i = 2, n_f = 1

`bar"v"_1 = "R"[1/1 - 1/4] = 3/4"R"`

`therefore bar"v"_2 = "R" [1/1 - 1/9] = 8/9"R"`

`bar"v"_3 = "R" [1 - 1/16] = 15/16"R"`