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प्रश्न
How are various lines of Lyman series formed? Explain on the basis of Bohr’s theory.
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उत्तर
We know,
`1/lambda = "R"_∞ [1/("n"_"f"^2 )- 1/"n"_"i"^2]`
If ni = 2,3,4
nf =1
For the member, ni = 2, nf = 1
`bar"v"_1 = "R"[1/1 - 1/4] = 3/4"R"`
`therefore bar"v"_2 = "R" [1/1 - 1/9] = 8/9"R"`
`bar"v"_3 = "R" [1 - 1/16] = 15/16"R"`
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