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प्रश्न
Given \[y=a\sin(x+b)\], where \[a,b\in R\], what is \[\frac{dy}{dx}\]?
पर्याय
\[\frac{dy}{dx}=-a\cos(x+b)\]
\[\frac{dy}{dx}=-a\sin(x+b)\]
\[\frac{dy}{dx}=a\sin(x+b)\]
\[\frac{dy}{dx}=a\cos(x+b)\]
MCQ
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उत्तर
The derivative of \[\sin(x+b)\] is \[\cos(x+b)\]. Since \[a\] is constant, \[\frac{dy}{dx}=a\cos(x+b)\].
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