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Given that CX(g)+OX2X(g)⟶COX2X(g) ∆H° = – a kJ; 2COX(g)+OX2X(g)⟶2COX2X(g) ∆H° = – b kJ; Calculate the ∆H° for the reaction CX(g)+12OX2X(g)⟶COX(g) - Chemistry

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प्रश्न

Given that \[\ce{C_{(g)} + O2_{(g)} -> CO2_{(g)}}\] ∆H° = – a kJ; \[\ce{2CO_{(g)} + O2_{(g)} -> 2CO2_{(g)}}\] ∆H° = – b kJ; Calculate the ∆H° for the reaction \[\ce{C_{(g)} + 1/2O2_{(g)} -> CO_{(g)}}\]

पर्याय

  • `("b" + 2"a")/2`

  • 2 − b

  • `(2"a" - "b")/2`

  • `("b" - 2"a")/2`

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उत्तर

`("b" - 2"a")/2`

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Measurement of ΔU and ΔH Using Calorimetry
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पाठ 7: Thermodynamics - Evaluation [पृष्ठ २२२]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
पाठ 7 Thermodynamics
Evaluation | Q I. 17. | पृष्ठ २२२

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