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प्रश्न
Given log 2 = a, log 3 = b, express in terms of a and b.
log 125
बेरीज
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उत्तर
Given: log 2 = a, log 3 = b
To Find: log 125
Calculation:
Step 1: Express 125 as a power of 5:
125 = 53
Thus:
log 125 = log (53) = 3 log 5
Step 2: Express log 5 in terms of a and b:
We know that:
log 10 = 1 and log 10 = log (2 × 5)
Using the property log (ab) = log a + log b, we get:
1 = log 2 + log 5
Since log 2 = a, we have:
1 = a + log 5
So:
log 5 = 1 – a
Step 3: Substitute and simplify:
Now substitute log 5 = 1 – a into the equation for log 125:
log 125 = 3 log 5
log 125 = 3 (1 – a)
log 125 = 3 – 3a
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पाठ 7: Logarithms - MISCELLANEOUS EXERCISE [पृष्ठ ७७]
