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प्रश्न
Given, B = magnetic induction and R = radius of the path, the energy of a charged particle coming out of a cyclotron is given by ______.
पर्याय
`(qB^2R^2)/(2m)`
`(q^2BR^2)/(2m)`
`(q^2BR)/(2m)`
`(q^2B^2R^2)/(2m)`
MCQ
रिकाम्या जागा भरा
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उत्तर
Given, B = magnetic induction and R = radius of the path, the energy of a charged particle coming out of a cyclotron is given by `bbunderline((q^2B^2R^2)/(2m)`).
Explanation:
Given: B = magnetic induction
R = radius of the path,
Formula: R = `(mv)/(qB)`
mv = RqB
Thus kinetic energy,
K = `1/2 mv^2`
= `(RqB)^2/(2m)`
= `(q^2B^2R^2)/(2m)`
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