Advertisements
Advertisements
प्रश्न
Given: ABCD is a rhombus, DPR and CBR are straight lines.
Prove that: DP × CR = DC × PR.
बेरीज
Advertisements
उत्तर
In ∆DPA and ∆RPC,
∠DPA = ∠RPC ...(Vertically opposite angles)
∠PAD = ∠PCR ...(Alternate angles)
∆DPA ~ ∆RPC
∴ `(DP)/(PR) = (AD)/(CR)`
`(DP)/(PR) = (DC)/(CR)` ...(AD = DC, as ABCD is rhombus)
Hence, DP × CR = DC × PR
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
