मराठी

Given A ≡ (x, x + 1) and B ≡ (3, 7). Find x, if AB = 15 units. - Mathematics

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प्रश्न

Given A ≡ (x, x + 1) and B ≡ (3, 7). Find x, if AB = 15 units.

बेरीज
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उत्तर

Given:

Points A = (x, x + 1) and B = (3, 7)

Distance (AB = 15 ) units

The distance formula between two points (x1, y1) and (x2, y2)

\[AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]

Substitute points A = (x, x + 1) and B = (3, 7) and distance AB = 15

\[15 = \sqrt{(3 - x)^2 + (7 - (x+1))^2} \]

\[15 = \sqrt{(3 - x)^2 + (7 - x - 1)^2} \]

\[15 = \sqrt{(3 - x)^2 + (6 - x)^2} \]    ... [Simplify inside the square root.]

152 = (3 − x)2 + (6 − x) ... [Square both sides to remove the square root.]

225 = (3 − x)2 + (6 − x)2

225 = (3 − x)2 + (6 − x)2 = (x − 3)2 + (x − 6)2    ...[Expand the squares]

225 = (x2 − 6x + 9) + (x2 − 12x + 36)

225 = 2x2 − 18x + 45 

2x2 − 18x + 45 − 225 = 0

2x2 − 18x − 180 = 0

x2 − 9x − 90 = 0     ... [Simplify by dividing the entire equation by 2.]

Factors of (−90) that add to (−9) are (+6) and (−15)

(x − 15) (x + 6) = 0 

x − 15 = 0 

x = 15

x + 6 = 0

x = −6

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पाठ 21: Coordinate Geometry - EXERCISE 21C [पृष्ठ २६१]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 21 Coordinate Geometry
EXERCISE 21C | Q 17. | पृष्ठ २६१
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