Question

Give the ionisation behaviour of the following salt:

Mohr’s salt

Answer 1

The formula of Mohr’s salt is FeSO₄⋅(NH₄)₂SO₄⋅6H₂O.

Mohr’s salt is a double salt, so it dissociates completely in aqueous solution into its constituent ions:

\[\ce{ FeSO4⋅(NH4)2SO4 -> Fe^2+ + 2NH+_4 + 2SO^2-_4}\]

In solution, Mohr’s salt furnishes is \[\ce{Fe^2+,2NH+_4, 2SO^2-_4}\].