Advertisements
Advertisements
प्रश्न
Give the expression for work done by the gas.
Advertisements
उत्तर
When a gas expands against pressure, it does work on the surroundings. The work done in expansion for volume V1 to V2 is given by
W = `int_("V"_1)^("V"_2) "PdV"`
If the pressure remains constant during expansion,
Then W = P(V2 – V1) = P∆V
If the volume remains constant, then W = 0.
If there is no external pressure, then no work is done. For example, when a gas expands freely in a vacuum, no work is done by it.
APPEARS IN
संबंधित प्रश्न
An ideal gas is taken from (Pi, Vi) to (Pf, Vf) in three different ways. Identify the process in which the work done on the gas the most.
Define the internal energy of the system.
Define one calorie.
Can we measure the temperature of the object by touching it?
What is a PV diagram?
Explain Joule’s Experiment of the mechanical equivalent of heat.
Derive the expression for the work done in a volume change in a thermodynamic system.
When a system absorbs 8 kJ of heat and does 2.2 kJ of work on surrounding, calculate the internal energy change.
An ideal gas expands against a constant external pressure of 2.0 atmosphere from 20 litre to 40 litre and absorbs 10 kJ of heat from the surrounding. What is the change in the internal energy of the system?
(Given: 1 atm-litre = 101.3 J)
A gas is allowed to expand in a well insulated container against a constant external pressure of 2.5 Bar from an initial volume of 2.5L to a final volume of 4.5L The change in internal energy, ΔU of the gas will be ______.
