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प्रश्न
Give a balanced chemical equation for the following :
Action of alcoholic KOH on bromoethane
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उत्तर
\[\ce{CH3CH2Br + KOH -> CH2 = CH2 + KBr + H2O}\]
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\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{Cl}\phantom{..}\ce{H}\phantom{...}\ce{H}\end{array}\]
