Question

Give at least one example to show the structure of isomers of double bond compounds.

Answer 1

In pentene,

\[\ce{\underset{1-pentene}{CH2=CH-CH2-CH2-CH3}}\]

\[\ce{\underset{2-pentene}{CH3-CH=CH-CH2-CH3}}\]

\[\begin{array}{cc}
\ce{CH2=C-CH2-CH3}\\
|\phantom{......}\\
\ce{\underset{isopentene}{CH3}}\phantom{...}
\end{array}\]

\[\begin{array}{cc}
\ce{CH3-C=CH-CH3}\\
|\phantom{.....}\\
\ce{\underset{isopentene}{CH3}}\phantom{..}
\end{array}\]

Answer 2

\[\begin{array}{cc}
\phantom{.}\ce{H}\phantom{..............}\ce{H}\phantom{....}\ce{H}\phantom{.}\\
|\phantom{...............}|\phantom{.....}|\phantom{.}\\
\ce{H - C^1 - C^2 = C^3 - C^4 - C^5 - H}\\
|\phantom{.....}|\phantom{.....}|\phantom{.....}|\phantom{.....}|\phantom{.}\\
\phantom{.}\ce{H}\phantom{....}\ce{H}\phantom{....}|\phantom{.....}\ce{H}\phantom{....}\ce{H}\phantom{.}\\
\ce{H - C - H}\phantom{..}\\
|\phantom{..}\\
\ce{\underset{3-methyl pent-2-ene}{H}}\phantom{.}\\
\end{array}\]