मराठी

Give a Balanced Equation for the Following Conversion. \\Ce{Mgcl2<-hcl->Fecl2}\

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प्रश्न

Give a balanced equation for the following conversion.

\[\ce{KAlO2<-KOH->K2ZnO2}\]

एका वाक्यात उत्तर
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उत्तर

\[\ce{2Al + 2KOH + 2H2O->2KAlO2 + 3H2}\]
\[\ce{Zn + 2KOH->K2ZnO2 + H2}\]

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Preparation of Hydrogen
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पाठ 6: Study of The First Element - Hydrogen - Hydrogen

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विराफ जे. दलाल Simplified ICSE Chemistry [English] Class 9
पाठ 6 Study of The First Element - Hydrogen
Hydrogen | Q 2.2

संबंधित प्रश्‍न

TRUE \ FALSE

reacts with hot water to form copper oxide and hydrogen.


Give a reason for the following:

Zinc granules are used in the lab preparation of hydrogen.


Give reason for the following:

Dilute sulphuric acid cannot be replaced by concentrated acid in the preparation of hydrogen.


Hydrogen can be prepared with the help of cold water. Give a reaction of hydrogen with:

A divalent metal 


Starting from hydrogen gas how would you obtain a metal by reduction of its heated oxide.


On heating which of the following substances i.e. copper carbonate, zinc carbonate, washing soda, copper sulphate, zinc nitrate, copper nitrate, lead nitrate, ammonium chloride and ammonium dichromate – relate to the reaction given below.

A white substance which leaves an amphoteric oxide as a residue [whose colour varies in the heated and in the cold state] and evolves a gas which turns lime water milky.


Complete and balance the equation:

[General method]

Reactions of active metals - cold water

Calcium - Ca + H2O → ______+ _______ [g]


Account for the following fact:

Potassium and sodium are not used to react with dilute ‘hydrochloric acid or dilute sulphuric acid in the laboratory preparation of hydrogen.


State the electronic configuration of hydrogen [at. no. 1].e
Give a reason why hydrogen can be placed in group 1 [1A] and group 17 [VIIA] of the periodic table.


Select the correct answer to the reactant added, to give the product in the preparation of hydrogen gas.

\[\ce{Fe3O4 + H2}\]


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