Question

From the top of a cliff 92 m high, the angle of depression of a buoy is 20°. Calculate, to the nearest metre, the distance of the buoy from the foot of the cliff.

Answer 1

Let AB be the cliff and C be the buoy. 

Given, AB = 92 m 

Also, ∠ACB = 20°

∴`(AB)/(BC) = tan 20^circ`

`=> BC = 92/0.3640 = 252.7  m ≈ 253  m`

Hence, the buoy is at a distance of 253 m from the foot of the cliff.