Advertisements
Advertisements
प्रश्न
From one vertex of an equilateral triangle with side 40 cm, an equilateral triangle with 6 cm side is removed. What is the perimeter of the remaining portion?
Advertisements
उत्तर
If an equilateral triangle of side 6 cm is removed the perimeter
= (40 + 34 + 6 +34) cm
= 114 cm
Perimeter of the remaining portion = 114 cm
APPEARS IN
संबंधित प्रश्न
AD is altitude of an isosceles triangle ABC in which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way that ∠BOC = 90o. Find the area of quadrilateral ABOC.
The area of an equilateral triangle is 36`sqrt3` sq. cm. Find its perimeter.
The base of a triangular field is three times its height. If the cost of cultivating the field at ₹ 36.72 per 100 m2 is ₹ 49,572; find its base and height.
The base and the height of a triangle are in the ratio 4: 5. If the area of the triangle is 40 m2; find its base and height.
The area of an equilateral triangle is `144sqrt3` cm2; find its perimeter.
The altitude and the base of a triangular field are in the ratio 6: 5. If its cost is ₹ 49,57,200 at the rate of ₹ 36,720 per hectare and 1 hectare = 10,000 sq. m, find (in metre) dimensions of the field.
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.
The perimeter of a triangle is 72cm and its sides are in the ratio 3:4:5. Find its area and the length of the altitude corresponding to the longest side.
The table given below contains some measures of the triangle. Find the unknown values.
| Side 1 | Side 2 | Side 3 | Perimeter |
| 11 feet | ? | 9 feet | 28 feet |
Find the perimeter of the triangle, whose sides are 13 cm, 5 cm and 14 cm
