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प्रश्न
For \[y=x^{\sin x}\], \[x>0\], what equation results after taking logarithm on both sides?
पर्याय
\[\log y=x\log(\sin x)\]
\[\log y=\sin x+x\]
\[\log y=\frac{\log x}{\sin x}\]
\[\log y=\sin x\log x\]
MCQ
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उत्तर
For \[x^{\sin x}\], the logarithm rule gives \[\log(x^{\sin x})=\sin x\log x\]. The condition \[x>0\] ensures that \[\log x\] is defined.
shaalaa.com
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