मराठी

For \[y+\sin y=\cos x\], which equation results after differentiating both sides with respect to \[x\] and using the chain rule?

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प्रश्न

For \[y+\sin y=\cos x\], which equation results after differentiating both sides with respect to \[x\] and using the chain rule?

पर्याय

  • \[\frac{dy}{dx}+\sin y\cdot\frac{dy}{dx}=\cos x\]

  • \[\frac{dy}{dx}+\cos y=-\sin x\]

  • \[y+\cos y=-\sin x\]

  • \[\frac{dy}{dx}+\cos y\cdot\frac{dy}{dx}=-\sin x\]

MCQ
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उत्तर

The derivative of \[y\] is \[\frac{dy}{dx}\]. Also, \[\frac{d}{dx}(\sin y)=\cos y\cdot\frac{dy}{dx}\], while \[\frac{d}{dx}(\cos x)=-\sin x\].

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