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प्रश्न
For \[y+\sin y=\cos x\], which equation results after differentiating both sides with respect to \[x\] and using the chain rule?
पर्याय
\[\frac{dy}{dx}+\sin y\cdot\frac{dy}{dx}=\cos x\]
\[\frac{dy}{dx}+\cos y=-\sin x\]
\[y+\cos y=-\sin x\]
\[\frac{dy}{dx}+\cos y\cdot\frac{dy}{dx}=-\sin x\]
MCQ
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उत्तर
The derivative of \[y\] is \[\frac{dy}{dx}\]. Also, \[\frac{d}{dx}(\sin y)=\cos y\cdot\frac{dy}{dx}\], while \[\frac{d}{dx}(\cos x)=-\sin x\].
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