Question

For the following polynomial, find p(1), p(0) and p(-2).

p(x) = x⁴ − 2x² − x

Answer 1

p(x) = x⁴ − 2x² − x

∴ p(1) = (1)⁴ − 2 × (1)² − 1

= 1 − 2 − 1

= −2

∴ p(0) = (0)⁴ − 2 × (0)² − 0

= 0 − 0 − 0

= 0

∴ p(−2) = (−2)⁴ − 2 × (−2)² − (−2)

= 16 − 2 × 4 + 2

= 16 − 8 + 2

= 10