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For the demand function D = 100 – p22. Find the elasticity of demand at p = 10 and comment on the results. - Mathematics and Statistics

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प्रश्न

For the demand function D = 100 – `p^2/2`. Find the elasticity of demand at p = 10 and comment on the results.

बेरीज
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उत्तर

Given, demand function is D = 100 – `p^2/2`

∴ `(dD)/(dp) = 0 - (2p)/2 = - p`

`eta = (-p)/D . (dD)/(dp)`

∴ `eta = (-p)/(100 - p^2/2).(-p)`

= `p^2/((200 - p^2)/2)`

∴ `eta = (2p)^2/(200 - p^2)`

When p = 10,

`eta = (2(10)^2)/(200 - (10)^2) = 200/100` = 2

∴ Elasticity of demand at p = 10 is 2

Here, η > 0

∴ The demand is elastic.

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पाठ 4: Applications of Derivatives - Exercise 4.4 [पृष्ठ ११३]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 4 Applications of Derivatives
Exercise 4.4 | Q 11.1 | पृष्ठ ११३

संबंधित प्रश्‍न

A manufacturing company produces x items at the total cost of Rs (180 + 4x). The demand function of this product is P = (240 − x). Find x for which profit is increasing.


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The total cost function for production of x articles is given as C = 100 + 600x – 3x2 . Find the values of x for which total cost is decreasing.


The total cost of manufacturing x articles C = 47x + 300x2 – x4 . Find x, for which average cost is decreasing


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If the demand function is D = `((p + 6)/(p − 3))`, find the elasticity of demand at p = 4.


For the demand function D = 100 – `"p"^2/2`. Find the elasticity of demand at p = 6 and comment on the results.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which revenue is increasing.


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price is given as p = 120 – x. Find the value of x for which also find an elasticity of demand for price 80.


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Fill in the blank:

A road of 108 m length is bent to form a rectangle. If the area of the rectangle is maximum, then its dimensions are _______.


If the marginal revenue is 28 and elasticity of demand is 3, then the price is ______.


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The manufacturing company produces x items at the total cost of ₹ 180 + 4x. The demand function for this product is P = (240 − 𝑥). Find x for which profit is increasing


A manufacturing company produces x items at a total cost of ₹ 40 + 2x. Their price per item is given as p = 120 – x. Find the value of x for which profit is increasing

Solution: Total cost C = 40 + 2x and Price p = 120 − x

Profit π = R – C

∴ π = `square`

Differentiating w.r.t. x,

`("d"pi)/("d"x)` = `square`

Since Profit is increasing,

`("d"pi)/("d"x)` > 0

∴ Profit is increasing for `square`


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Ec = (0.0003)I2 + (0.075)I2

when I = 1000


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If 0 < η < 1 then the demand is ______.


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