मराठी

For \[\sqrt{\frac{x-\alpha}{\beta-x}}\] or \[\sqrt{(x-\alpha)(\beta-x)}\], where \[\beta>\alpha\], which substitution is used?

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प्रश्न

For \[\sqrt{\frac{x-\alpha}{\beta-x}}\] or \[\sqrt{(x-\alpha)(\beta-x)}\], where \[\beta>\alpha\], which substitution is used?

पर्याय

  • \[x=a\sin^2\theta\]

  • \[x=a\cos 2\theta\]

  • \[x=\alpha\sin^2\theta+\beta\cos^2\theta\]

  • \[x=\alpha\cos^2\theta+\beta\sin^2\theta\]

MCQ
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उत्तर

When \[\beta>\alpha\], use \[x=\alpha\cos^2\theta+\beta\sin^2\theta\]. This substitution is designed for the factors \[x-\alpha\] and \[\beta-x\].

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