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प्रश्न
For an acute angle θ, if `sin θ = 1/9`, then value of `(9 "cosec" θ + 1)/(9 "cosec" θ - 1)` is ______.
पर्याय
0
`80/81`
1
`82/80`
MCQ
रिकाम्या जागा भरा
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उत्तर
For an acute angle θ, if `sin θ = 1/9`, then value of `(9 "cosec" θ + 1)/(9 "cosec" θ - 1)` is `underlinebb(82/80)`.
Explanation:
Given: `sin θ = 1/9`
Therefore, `"cosec" θ = 1/(sin θ) = 9`.
`(9 "cosec" θ + 1)/(9 "cosec" θ - 1)`
= `(9(9) + 1)/(9(9) - 1)`
= `(81 + 1)/(81 - 1)`
= `82/80`
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