Advertisements
Advertisements
प्रश्न
Find the values of the letters in the following and give reasons for the steps involved
A B
x 3
-------
C A B
-------
Advertisements
उत्तर
The multiplication of 3 and B gives a number whose ones digit is B again.
Hence, B must be 0 or 5.
Let B is 5.
Multiplication of first step = 3 × 5 = 15
1 will be a carry for the next step.
We have, 3 × A + 1 = CA
This is not possible for any value of A.
Hence, B must be 0 only. If B = 0, then there will be no carry for the next step.
We should obtain, 3 × A = CA
That is, the one’s digit of 3 × A should be A. This is possible when A = 5 or 0.
However, A cannot be 0 as AB is a two-digit number.
Therefore, A must be 5 only. The multiplication is as follows
50
x 3
-----
150
-----
Hence, the values of A, B, and C are 5, 0, and 1 respectively.
APPEARS IN
संबंधित प्रश्न
Find the values of the letters in the following and give reasons for the steps involved.
A B
x 5
-------
C A B
-------
Find the values of the letters in the following and give reasons for the steps involved.
A 1
+ 1 B
-------
B 0
-------
Find the values of the letters in the following and give reasons for the steps involved.
2 A B
+ A B 1
---------
B 1 8
----------
| A | |
| + | A |
| + | A |
| B | A |
If 
then A = ______ and B = ______.
If 
where Q – P = 3, then find the values of P and Q.
Find the value of the letters in the following question.
8 5
+ 4 A
B C 3
212 × 5 is a multiple of 3 and 11. Find the value of x.
Let D = 3, L = 7 and A = 8. Find the other digits in the sum
M A D
+ A S
+ A
B U L L
Find the value of the letters in the following:
2 L M
+ L M 1
M 1 8
